I have some ceramic capacitors and would like to know for sure what capacitance they have.I don't have a multimeter (or any other instrument) that allows me to measure capacitance directly, so I build a simple RC filter that filters a square wave input, I know that the voltage at the output at the time constant R*C is 63% of Vinput ... I reverse the formula and find C.
The question (which is probably stupid) is whether I can use as input the square wave produced by the oscilloscope (is usually used to check before each measurement if the probe is correctly calibrated) .. otherwise I would need a square wave generator :/
After the responses I received, I will upload the photo of the calculations made and ask if they are correct:(565mV is the V measured with the CH1 probe at the ends of 220 ohms)EDIT: missing a multiplication by 2 in the equation! With that multiplication, the result is about 560 ohms which is correct because I used a 500ohm + 100ohm series finding about 1Vpp at the output .. which is half of 2Vpp
I tried measuring a 100nF capacitor but obtained 36nF:
